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6z^2+80z+26=0
a = 6; b = 80; c = +26;
Δ = b2-4ac
Δ = 802-4·6·26
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-76}{2*6}=\frac{-156}{12} =-13 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+76}{2*6}=\frac{-4}{12} =-1/3 $
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